C program to reverse an array
C
program to reverse an array: This program reverses the array elements.
For example if a is an array of integers with three elements such that
a[0] = 1
a[1] = 2
a[2] = 3
Then on reversing the array will be
a[0] = 3
a[1] = 2
a[0] = 1
Given below is the c code to reverse an array.
Download Reverse array program.
Output of program:
Array is passed to function and a new array is created and contents
of passed array (in reverse order) are copied into it and finally
contents of new array are copied into array passed to function.
a[0] = 1
a[1] = 2
a[2] = 3
Then on reversing the array will be
a[0] = 3
a[1] = 2
a[0] = 1
Given below is the c code to reverse an array.
C programming code
#include <stdio.h> int main() { int n, c, d, a[100], b[100]; printf("Enter the number of elements in array\n"); scanf("%d", &n); printf("Enter the array elements\n"); for (c = 0; c < n ; c++) scanf("%d", &a[c]); /* * Copying elements into array b starting from end of array a */ for (c = n - 1, d = 0; c >= 0; c--, d++) b[d] = a[c]; /* * Copying reversed array into original. * Here we are modifying original array, this is optional. */ for (c = 0; c < n; c++) a[c] = b[c]; printf("Reverse array is\n"); for (c = 0; c < n; c++) printf("%d\n", a[c]); return 0; }
Output of program:
Reverse array by swapping (without using additional memory)
#include <stdio.h> int main() { int array[100], n, c, t, end; scanf("%d", &n); end = n - 1; for (c = 0; c < n; c++) { scanf("%d", &array[c]); } for (c = 0; c < n/2; c++) { t = array[c]; array[c] = array[end]; array[end] = t; end--; } printf("Reversed array elements are:\n"); for (c = 0; c < n; c++) { printf("%d\n", array[c]); } return 0; }
C program to reverse an array using pointers
#include <stdio.h> #include <stdlib.h> void reverse_array(int*, int); int main() { int n, c, *pointer; scanf("%d",&n); pointer = (int*)malloc(sizeof(int)*n); if( pointer == NULL ) exit(EXIT_FAILURE); for ( c = 0 ; c < n ; c++ ) scanf("%d",(pointer+c)); reverse_array(pointer, n); printf("Original array on reversal is\n"); for ( c = 0 ; c < n ; c++ ) printf("%d\n",*(pointer+c)); free(pointer); return 0; } void reverse_array(int *pointer, int n) { int *s, c, d; s = (int*)malloc(sizeof(int)*n); if( s == NULL ) exit(EXIT_FAILURE); for ( c = n - 1, d = 0 ; c >= 0 ; c--, d++ ) *(s+d) = *(pointer+c); for ( c = 0 ; c < n ; c++ ) *(pointer+c) = *(s+c); free(s); }
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